compagnia04
2021-12-25
Answered

The series is,

$\sum _{n=9}^{\mathrm{\infty}}\frac{1}{n(n-1)}$

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Toni Scott

Answered 2021-12-26
Author has **32** answers

Fasaniu

Answered 2021-12-27
Author has **46** answers

the general method:

This is why you get

and then (keep the first term for the lower index and the last with the bigger)

user_27qwe

Answered 2021-12-30
Author has **208** answers

Now write out some terms:

It's clear that the

Now take the limit as N goers to infinity:

asked 2022-01-23

Proof that:

$\sum _{n=0}^{\mathrm{\infty}}\frac{1}{n!}=e$

asked 2021-07-03

Suppose you take a dose of m mg of a particular medication once per day. Assume f equals the fraction of the medication that remains in your blood one day later. Just after taking another dose of medication on the second day, the amount of medication in your blood equals the sum of the second dose and the fraction of the first dose remaining in your blood, which is m+mf. Continuing in this fashion, the amount of medication in your blood just after your nth does is

asked 2022-01-23

Sum of series:

$\sum _{n=1}^{\mathrm{\infty}}\frac{1}{4{n}^{2}-1}$

asked 2022-04-19

What is

$\sum _{n=0}^{\mathrm{\infty}}\frac{2{n}^{7}+{n}^{6}+{n}^{5}+2{n}^{2}}{n!}$

asked 2021-09-06

asked 2022-02-24

Identify

$f\left(x\right)=\sum _{k=-\mathrm{\infty}}^{\mathrm{\infty}}\frac{1}{{(x+k)}^{2}}$

asked 2022-02-28

What is the idea to sum this series of powers?

$\sum _{n=1}^{+\mathrm{\infty}}({n}^{2}+n+1){x}^{n-1}$