How do you solve $2x{(x-5)}^{-1}+\frac{1}{x}=0$

keche0b
2021-12-22
Answered

How do you solve $2x{(x-5)}^{-1}+\frac{1}{x}=0$

You can still ask an expert for help

Jimmy Macias

Answered 2021-12-23
Author has **30** answers

Explanation:

$2{(x-5)}^{-1}+\frac{1}{x}=0$

Re-arrange the terms to have one fraction on each side. (note that the negative index moves the bracket to the denominator)

$x\ne +5$ and $x\ne 0$

$\frac{2}{x-5}=\frac{-1}{x}$

$2x=-x+5$

$3x=5$

$x=\frac{53}{}$

Re-arrange the terms to have one fraction on each side. (note that the negative index moves the bracket to the denominator)

Jillian Edgerton

Answered 2021-12-24
Author has **34** answers

Explanation:

We have:$2{(x-5)}^{-1}+\frac{1}{x}=0$

The terms within the parentheses can be expressed as a fraction:

$\Rightarrow 2\cdot \frac{1}{x-5}+\frac{1}{x}=0$

$\Rightarrow \frac{2}{x-5}+\frac{1}{x}=0$

Lets

We have:

The terms within the parentheses can be expressed as a fraction:

Lets

karton

Answered 2021-12-30
Author has **368** answers

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