Solve the initial value problem. 4x^2y''+17y=0, y(1)=-1, y'(1)=-1/2

ediculeN 2021-01-04 Answered
Solve the initial value problem.
4x2y+17y=0,y(1)=1,y(1)=12
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Answered 2021-01-05 Author has 91 answers

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