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nemired9

Answered question

2021-12-25

At STP, 0.280 L of a gas weighs 0.400 g. Calculate the molar mass of the gas.

Answer & Explanation

jean2098

Beginner2021-12-26Added 38 answers

Given information:
The volume of a gas -

V = 0.280 L

at STP, standard temperature and pressure -

T = 273 K, P = 1 a t m

Mass of the gas -

m = 0.400 g

Ideal gas constant

R = 0.0821 L \cdot a t \frac{m}{K} \cdot m o l

Let us calculate the molar mass of the gas (M).
We know that

m = \frac{m}{M}

Using the ideal gas law, we get

P V = n R T

P V = \frac{m}{M} \cdot R T

M = \frac{m R T}{P V}

= \frac{0.400 g \cdot 0.0821 L \cdot a t \frac{m}{K} \cdot m o l \cdot 273 K}{1 a t m \cdot 0.280 L}

\approx 32 \frac{g}{m} o l

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