(n+4)(n+5)(n+3)!=(n+4)(n+5)(n+3)(n+2)(n+1)n

(n+4)(n+5)(n+3)!=(n+5)!

(n+4)(n+5)(n+3)!=(n+5)!

lalilulelo2k3eq

Answered 2021-12-22
Author has **2680** answers

asked 2021-12-20

Simplify, please:

\(\displaystyle{\frac{{{n}!}}{{{\left({n}-{3}\right)}!}}}\)

\(\displaystyle{\frac{{{n}!}}{{{\left({n}-{3}\right)}!}}}\)

asked 2021-12-10

Simplify, please: \(\displaystyle{\frac{{{12}!}}{{{8}!{4}!}}}\)

asked 2021-12-10

Simplify the factorial expression \(\displaystyle{\frac{{{\left({n}+{1}\right)}!}}{{{n}!}}}\)

asked 2021-09-24

If X has a binomial distribution, \(\displaystyle{n}={5}\ {\quad\text{and}\quad}\ {p}={0.4}\). Determine the probabilities of \(\displaystyle{X}={0}\).

a). -1.2321

b) 0.07776

c) 0.1073741824

d) 0.1534621

a). -1.2321

b) 0.07776

c) 0.1073741824

d) 0.1534621

asked 2021-12-12

What does it mean 5C3? Solve, please.

asked 2021-09-17

Use the binomial probability formula to find \(\displaystyle{P}{\left({x}\right)}{n}={16},{x}={3},{p}-{\frac{{{1}}}{{{5}}}}\)

asked 2021-09-09

Use the binomial probability formula to find \(P(x) \)

\(n= 16,\ x=3,\ p- \frac{1}{5}\)