Solve, please. \cos(2x)=1

Ernest Ryland 2021-12-20 Answered
Solve, please. \(\displaystyle{\cos{{\left({2}{x}\right)}}}={1}\)

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

autormtak0w
Answered 2021-12-21 Author has 469 answers
Isolate the variable by dividing each side by factors that don't contain the variable.
\(\displaystyle{x}=\pi{n}\) for any integer n
Not exactly what you’re looking for?
Ask My Question
0
 
Toni Scott
Answered 2021-12-22 Author has 3563 answers
\(\displaystyle{\cos{{\left({2}{x}\right)}}}={2}\), \(\displaystyle{{\cos}^{{{2}}}{x}}-{1}={1}\)
\(\displaystyle{{\cos}^{{{2}}}=}{1}\)
\(\displaystyle{\cos{{\left({x}\right)}}}={1}\), x=0 and \(\displaystyle{x}={2}\pi\)
\(\displaystyle{\cos{{\left({x}\right)}}}=-{1}\), \(\displaystyle{x}=\pi\)
0
RizerMix
Answered 2021-12-29 Author has 9350 answers

\(\cos(2x)=1\)
\(2x=2\pi k\)
\(x=\pi k\)
\(k\in Z\)

0

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more
...