# Use Cramer’s Rule to solve (if possible) the system of linear equations. 2x-y=-10 3x+2y=-1

Use Cramer’s Rule to solve (if possible) the system of linear equations.
2x-y=-10
3x+2y=-1
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Here,
$D=\left[\begin{array}{cc}2& -1\\ 3& 2\end{array}\right]=4-\left(-3\right)=7$
${D}_{x}=\left[\begin{array}{cc}-10& -1\\ -1& 2\end{array}\right]=-20-1=-21$
${D}_{y}=\left[\begin{array}{cc}2& -10\\ 3& -1\end{array}\right]=-2-\left(30\right)=28$
By using cramer's rule
$x=\frac{{D}_{x}}{D}=\frac{\left(-21\right)}{7}=-3$
$y=\frac{{D}_{y}}{D}=\frac{28}{7}=4$
Thus,
x=-3
y=4