# find each value of a and b solving the linear equationsx-w=2y-z+w=3az=1y+bw=0

find each value of a and b solving the linear equations
$x-w=2$
$y-z+w=3$
$az=1$
$y+bw=0$

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Isma Jimenez

Given linear equations are,
$x-w=2,y-z+w=3,az=1,y+bw=0$
Step 2
To find values of a and b.
Given equations are
$x-w=2...\left(1\right)$
$y-z+w=3...\left(2\right)$
$az=1...\left(3\right)$
$y+bw=0...\left(4\right)$
from equation(3) $z=\frac{1}{a}$
from equation(1)$w=x-2$
substitute value of z and
$y-1a+x-2=3$
$⇒ay-1+ax-2a+3a$
$⇒ay-1+ax-5a=0$
$⇒ay+ax-5a=1$
$⇒a\left(y+x-5\right)=1$
$⇒a=\frac{1}{\left(y+x-5\right)}$
from equation (4) $y+bw=0⇒y=-bw$
$⇒b=\frac{-y}{w}$
substitute
$⇒b=\frac{-y}{x-2}$
Therefore the values of a and b are
$a=\frac{1}{y+x-5},b=\frac{-y}{x-2}$