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# Fill in the blank/s: When solving 3x^2 + 2y^2 = 35, 4x^2 + 3y^2 = 48 by the addition method, we can eliminate x2 by multiplying the first equation by -4 and the second equation by _________ and then adding the equations.

Equations and inequalities
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asked 2020-12-07
Fill in the blank/s: When solving $$3x^2 + 2y^2 = 35, 4x^2 + 3y^2 = 48$$ by the addition method, we can eliminate x2 by multiplying the first equation by -4 and the second equation by _________ and then adding the equations.

## Expert Answers (1)

2020-12-08
The equations given are $$3x^2 + 2y^2 = 35, 4x^2 + 3y^2 = 48$$.
We have to make the coefficients of $$x^2$$ with same numbers but of opposite signs.
Here the lcm of coefficients of $$x^2$$ in the first and second equations are lcm(3,4)=12. Thus, the we have to make the coefficients of x2 in the first and second equations as -12 and 12.
Thus, multiply the first equation by -4 and the second equation by 3 and then adding the equations.

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