Factor each of the algebraic expressions completely. 27x^{3} - 8y^{3}

bmgf3m 2021-12-17 Answered
Factor each of the algebraic expressions completely. 27x38y3
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Expert Answer

Samantha Brown
Answered 2021-12-18 Author has 35 answers
27x38y3
The formula for this expression is:
a3b3=(ab)(a2+ab+b2)
where a=3x and b=2y
(3x)3(2y)3=(3x2y)((3x)2+(3x)×(2y)+(2y)2)
=(3x2y)(9x2+6xy+4y2)
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Joseph Lewis
Answered 2021-12-19 Author has 43 answers
27x38y3
=(3x)3(2y)3
=(3x2y)((3x)2+(3x)(2y)+(2y)2)
=(3x2y)(32x2+6xy+22y2)
=(3x2y)(9x2+6xy+4y2)
=(3x2y)(9x2+6xy+4y2)
This is factored all the way.
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RizerMix
Answered 2021-12-29 Author has 438 answers

The formula for factoring the difference of cubes is: u3v3=(uv)(u2+uv+v2)
27x38y3=(3x)3(2y)3
u=3x and v=2y
(3x2y)((3x)2+(3x)(2y)+(2y)2)
(3x2y)(9x2+6xy+4y2)

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