Solve the following equation algebraically. Round to 2 decimal places.

tebollahb

tebollahb

Answered question

2021-12-21

Solve the following equation algebraically. Round to 2 decimal places. Show all work.
5ex+28=14

Answer & Explanation

Mason Hall

Mason Hall

Beginner2021-12-22Added 36 answers

Step 1
In the question we have to find value of x.
Step 2
5ex+28=14
5ex+2=14+8
5ex+2=22
ex+2=225
Taking log on both side
logex+2=log(225)
(x+2)ln(e)=1.4816{lne=1}
x+2=1.4816x=0.5184.
jgardner33v4

jgardner33v4

Beginner2021-12-23Added 35 answers

Step 1
Consider the equation
5ex+28=14
Step 2
5ex+28=14
On solving
5ex+2=14+8
ex+2=225
Take natural log on both sides
lnex+2=ln(225)
(x+2)lne=ln(4.4) (logab=bloga)
x+2=ln(4.4) (lne=1)
x=ln(4.4)2
x=0.518395
on rounding to two decimal places
x=0.52
Step 3
Answer: x=0.52
nick1337

nick1337

Expert2021-12-28Added 777 answers

Answer:
x=ln(4.4)2Z
Explanation:
5ex+28=14
5ex+2=22
ex+2=4.4
ln[ex+2]=ln4.4
x+2=ln4.4
x=ln(4.4)2

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