pogonofor9z
2021-12-17
Answered

Find the distance d between the points $P}_{1$ and $P}_{2$

${P}_{1}=(1.2,\text{}2.3)$

${P}_{2}=(-0.3,\text{}1.1)$

You can still ask an expert for help

Terry Ray

Answered 2021-12-18
Author has **50** answers

Step 1

The distance formula is given below so that we can calculate the distance between the two points then

$d=\sqrt{{({x}_{2}-{x}_{1})}^{2}+{({y}_{2}-{y}_{1})}^{2}}$

now the points are given that$P}_{1$ and $P}_{2$ which are (1.2, 2.3) and (-0.3, 1.1) respectively. and $({x}_{1},\text{}{y}_{1})=(1.2,\text{}2.3),\text{}({x}_{2},\text{}{y}_{2})=(-0.3,\text{}1.1)$

so${x}_{1}=1.2,\text{}{y}_{1}=2.3,\text{}{x}_{2}=-0.3,\text{}{y}_{2}=1.1$

now put the value into the distance formula

$d=\sqrt{{({x}_{2}-{x}_{1})}^{2}+{({y}_{2}-{y}_{1})}^{2}}$

${x}_{1}=1.2,\text{}{y}_{1}=2.3,\text{}{x}_{2}=-0.3,\text{}{y}_{2}=1.1$

$d=\sqrt{{(-0.3-1.2)}^{2}+{(1.1-2.3)}^{2}}$

$d=\sqrt{{(-1.5)}^{2}+{(-1.2)}^{2}}$

$d=\sqrt{{\left(1.5\right)}^{2}+{\left(1.2\right)}^{2}}$

$d=\sqrt{2.25+1.44}$

$d=\sqrt{3.69}$

$d=1.920937$

The distance formula is given below so that we can calculate the distance between the two points then

now the points are given that

so

now put the value into the distance formula

Jimmy Macias

Answered 2021-12-19
Author has **30** answers

Step 1

The question is taken from the Analytical Geometry in which we have to find the distance between the two points. The given points are P1 and P2 which are (1.2, 2.3) and (-0.3, 1.1) respectively.

Given that distance between the two points is d

Now we have to solve the question by using the distance formula

We move to the next step -2 to solve the question

Step 2

The distance formula is given below so that we can calculate the distance between the two points then

$d=\sqrt{{(x2-x1)}^{2}+{(y2-y1)}^{2}}$

now the points are given that P1 and P2 which are (1.2, 2.3) and (-0.3, 1.1) respectively.

and$\left(x1y1\right)=(1.2,2.3),\left(x2y2\right)=(-0.3,1.1)$

so$x1=1.2,y1=2.3,x2=-0.3,y2=1.1$

now put the value into the distance formula

$d=\sqrt{{(x2-x1)}^{2}+{(y2-y1)}^{2}}$

$x1=1.2,y1=2.3,x2=-0.3,y2=1.1$

$d=\sqrt{{(-0.3-1.2)}^{2}+{(1.1-2.3)}^{2}}$

$d=\sqrt{{(-1.5)}^{2}+{(-1.2)}^{2}}$

$d=\sqrt{{\left(1.5\right)}^{2}+{\left(1.2\right)}^{2}}$

$d=\sqrt{2.25+1.44}$

$d=\sqrt{3.69}$

$d=1.920937$

the result is shown in the step-3

Step 3 Result

Result: From the above solution we got the distance between two points P1 and P2 are shown below

$d=1.920937$ Answer

The question is taken from the Analytical Geometry in which we have to find the distance between the two points. The given points are P1 and P2 which are (1.2, 2.3) and (-0.3, 1.1) respectively.

Given that distance between the two points is d

Now we have to solve the question by using the distance formula

We move to the next step -2 to solve the question

Step 2

The distance formula is given below so that we can calculate the distance between the two points then

now the points are given that P1 and P2 which are (1.2, 2.3) and (-0.3, 1.1) respectively.

and

so

now put the value into the distance formula

the result is shown in the step-3

Step 3 Result

Result: From the above solution we got the distance between two points P1 and P2 are shown below

nick1337

Answered 2021-12-28
Author has **510** answers

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