The main objective of the problem is to find the p-value for the z test statistic 1.52.

The p-value is obtained below:

\(\displaystyle{p}−{v}{a}{l}{u}{e}={P}{\left({Z}{>}{1.52}\right)}\)

\(\displaystyle={1}-{P}{\left({Z}\le{1.52}\right)}\)

From the standard normal table, the value of \(\displaystyle{P}{\left({Z}\le{1.52}\right)}\) is \(\displaystyle{0.9357}\).

\(\displaystyle{p}−{v}{a}{l}{u}{e}={1}−{0.9357}\)

\(\displaystyle={0.0643}\)

The p-value is 0.0643.

The p-value is obtained below:

\(\displaystyle{p}−{v}{a}{l}{u}{e}={P}{\left({Z}{>}{1.52}\right)}\)

\(\displaystyle={1}-{P}{\left({Z}\le{1.52}\right)}\)

From the standard normal table, the value of \(\displaystyle{P}{\left({Z}\le{1.52}\right)}\) is \(\displaystyle{0.9357}\).

\(\displaystyle{p}−{v}{a}{l}{u}{e}={1}−{0.9357}\)

\(\displaystyle={0.0643}\)

The p-value is 0.0643.