# For a test of Ho: p = 0.5, the z

For a test of Ho: p = 0.5, the z test statistic equals -1.74. Find the p-value for Ha: p < 0.5.
a. 0.0892
b. 0.0446
c. 0.0409
d. 0.9554
e. 0.0818

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xandir307dc
Solution:- p value = 0.1286
Since we have a two-tailed test, the P-value is the probability that the z statistic is less than - 1.52 or greater than 1.52.
We use the z Distribution Calculator to find P(t < - 1.52) = 0.0643, and P(t > 1.52) = 0.0643
Thus, the P-value = 0.0643 + 0.0643 = 0.1286
Interpret results. Since the P-value (0.1286) is greater than the significance level (0.05), we cannot reject the null hypothesis.
From the test we conclude that we have sufficient evidence to support the claim that p = 0.5.
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nick1337
From the given information,
Null hypothesis:
H_0:p=0.5
Alternative hypothesis:
H_0:p<0.5
That is, the alternative hypothesis is one-sided hypothesis. Hence, the p-value is obtained for left tailed test.
From the given information, the value of test statistic is &ndash;1.74.
p=P(z<z)

=P(Z<-1.74)
From the standard normal table, the value of P(Z<&minus;1.74) is 0.0409.

Therefore,

p=P(Z<-1.74)
=0.0409
The p-value is  c. 0.0409.