A string of length L = 2.9 m and mass m = 0.095 kg is fixed between tw

Mary Buchanan 2021-12-18 Answered
A string of length L = 2.9 m and mass m = 0.095 kg is fixed between two stationary points, and when the string is plucked a transverse wave of frequency f = 84 Hz is generated.
Part A: What is the strings linear density, ρ, in kilograms per meter?
  Part B: If the wavelength is 10.0 cm, which harmonic is this, counting the fundamental as 1? 
Part C: For the case described in Part (b), what is the tension in N?
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Expert Answer

Travis Hicks
Answered 2021-12-19 Author has 29 answers
Given that the length of the string is 2.9m, and a mass of 0.095kg is fixed between the two stationary points. The frequency of the transverse wave is f = 84Hz.
Write the expression for linear mass density.
ρ=ML
=(0.095kg)2.9m
=0.0327kgm
a) The linear mass density is 0.0327kgm

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Annie Gonzalez
Answered 2021-12-20 Author has 41 answers
Write the relation between the length of the string and number of loop.
L=Nλ2
N=2Lλ
=2(2.9m)0.10m
= 58
The harmonic of the string wave is 58.

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nick1337
Answered 2021-12-27 Author has 575 answers

Write the expression for frequency.
f=Nv2L
v=2LfN
P=2(2.9m)(84Hz)58
=8.4m/s
The velocity can also be written as
v=Tρ
T=v2ρ
=(8.4m/s)2(0.0327kg/m)
=2.307N
c) The tension is 2.307 N.

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