When jumping, a flea reaches a takeoff speed of 1.0 m/s over a distanc

piarepm 2021-12-17 Answered
When jumping, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm.
a. What is the fleas
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Expert Answer

SlabydouluS62
Answered 2021-12-18 Author has 52 answers

Step 1
Given values:
viy=0ms
vfy=1ms
yi=0m
yf=0.5103m
g=9.81ms2
a) In this case, we have to determine value of acceleration. The best way to find that is using the kinematic equation:
vf2=vi2+2a(y).
Plug in values in above equation and solve for acceleratiion:
vfy2=viy2+2ay(yfyi)
(1ms)2=(0ms)+2ay(0.5103m0m)
(1m2s2=2ay(0.5103m)
ay=(1m2s2)2(0.5103m)
ay=1000ms2
Step 2
b) Use the kinematic equation to find value of time:
vfy=viy+ayt
Plug in values in above equation and solve for time:
1ms=0ms+(1000ms2)t
t=1ms0ms(1000ms2)
t=1ms(1000ms2)
t=103s
c) It is moving straight up, so it's final speed is equal to zero when it reaches the highest point is using the kinematic equation:
vf2=vi2+2a(y)
If we plug in values in above equation, we get:
vfy2=viy2+2ay(yfyi)

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Donald Cheek
Answered 2021-12-19 Author has 41 answers

Step 1
Part A.
Following equation will be used:
v2u2=2as
where v is the final velocity , u is the initial velocity, a is the acceleration and s is the distance traveled
Given values are as follows:
v=1ms,u=0ms,s=0.5×103m
Therefore, v2u2=2as
(1)2(0)2=2×a×5×103
a=100ms2
Step 2
Part B.
Here time is need to be calculated by following equation:
v=u+at
1=0+100×
t=0.01s
Part C.
If the flea jumps straight up then the acceleration due to gravity will be taken into account and following equation will be used.
v2u2=2gs
Given values are as follows:
v=0ms,u=1ms,g=9.8ms2
Therefore, v2u2=2gs
(0)2(1)2=2×9.8×s
s=0.051m

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