A chemist in an imaginary universe, where electrons have a different c

petrusrexcs

petrusrexcs

Answered question

2021-12-15

A chemist in an imaginary universe, where electrons have a different charge than they do in our universe, performs the Millikan oil drop experiment to measure the electrons

Answer & Explanation

Ben Owens

Ben Owens

Beginner2021-12-16Added 27 answers

Step 1
The Millikan experiment consisted of finding the minimum possible charge by obtaining the smallest drop possible. He then inferred that the charge of the electron was due to the fact that it was not possible to find a lower charge.
Drop #ChargeA 6.9×1019CB 9.2×1019CC 11.5×1019CD 4.6×1019C
Step 2
We must find a number that when we divide in the four drop # it would give us a quotient that is a whole number. We can do this by doing trial and error.
By trial and error, we found out that the number is 2.3×1019C
DROP A: 6.9×1019C2.3×1019C=3
DROP B: 9.2×1019C2.3×1019C=4
DROP C: 11.5×1019C2.3×1019C=5
DROP D: 4.6×1019C2.3×1019C=2
Answer: 2.3×1019C
Kindlein6h

Kindlein6h

Beginner2021-12-17Added 27 answers

Millikan experiment consisted in finding the minimum possible charge by obtaining the tiniest drop possible.
Then, he inferred that was the charge of the electron, given that it was not possible to find a lower charge.
Given these recorded data:
6.91019
9.21019
11.51019
4.61019
You must find a number that divide the four data and yields a whole number.
This number is 2.31019.
In that way you find:
6.910192.31019=33 electrons
9.210192.31019=44 electrons
11.510192.31019=55 electrons
4.610192.31019=22 electrons
And you can conclude that the charge of the electron is 2.31019
Answer: 2.31019
nick1337

nick1337

Expert2021-12-27Added 777 answers

Step 1
The idea is the number of electrons is a whole number. So to find a charge that a “whole multiple” will satisfy all the charges on the drops.
Step 2
Let X = the charge….A, B, C and D are whole.
AX=-5.7×10-19C.
BX=-7.6×10-19C.
CX=-9.5×10-19C.
DX=-3.8×10-19C.
Difference between BX and CX is 1.910-19.  That’s the smallest difference.
Step 3
Therefore,
3×(-1.910-19)=-5.7×10-19C
4×(-1.910-19)=-7.6×10-19C
5×(-1.910-19)=-9.5×10-19C
2×(-1.910-19)=-3.8×10-19C.
So the charge of imaginary electron is -1.910-19C

Andre BalkonE

Andre BalkonE

Skilled2023-06-12Added 110 answers

In an imaginary universe, let's assume that the charge of electrons, denoted as e, is different from our universe. A chemist performs the Millikan oil drop experiment to measure the charge of electrons in this universe.
The Millikan oil drop experiment involves suspending tiny oil droplets in an electric field and measuring their motion to determine the charge of the droplets. To begin, the chemist first adjusts the electric field such that the oil droplets are in equilibrium, neither rising nor falling.
The force experienced by an oil droplet in the electric field is given by the equation:
Felectric=q·E
where Felectric is the electric force, q is the charge of the oil droplet, and E is the strength of the electric field.
The weight of the droplet can be expressed as:
Fgravity=m·g
where Fgravity is the gravitational force, m is the mass of the droplet, and g is the acceleration due to gravity.
Since the droplet is in equilibrium, the electric force and the gravitational force must balance each other:
Felectric=Fgravity
q·E=m·g
The chemist then measures the terminal velocity of the droplet, which is the velocity at which the droplet is no longer accelerating in the electric field. This terminal velocity can be related to the droplet's mass and the properties of the fluid in which it is suspended.
By knowing the terminal velocity and using the equations above, the chemist can determine the charge of the oil droplet. However, since the charge of electrons in this imaginary universe is different from our universe, the chemist needs to account for the different value of e in the calculations.
To summarize, in this imaginary universe with different electron charge e, the chemist performs the Millikan oil drop experiment to measure the charge of the oil droplets. The equilibrium between the electric force and the gravitational force is used, and the terminal velocity of the droplets is measured to calculate their charge.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?