An iceberg (specific gravity 0.917) floats in the ocean (specific

Start by calculating the force of weight of the iceberg:
${\displaystyle F_w=S{G}_{ice}\cdot {\gamma }_{H_{2}O}\cdot V}$
${\displaystyle =0.917\cdot {\gamma }_{H_{2}O}\cdot V}$
${\displaystyle =0.917\cdot 62.4\frac{lb}{f{t}^3}\cdot V}$
${\displaystyle =57.22Vlb}$
The buoyancy force that acts upwards and opposes the force of weight is:
${\displaystyle F_b=S{G}_{seawater}\cdot {\gamma }_{H_{2}O}\cdot V^{\prime }}$
Where V' is the volume of the submerged part of the iceberg. Substituting the known values we obtain:
${\displaystyle F_b=1.025\cdot 62.4\frac{lb}{f{t}^3}\cdot V^{\prime }}$
${\displaystyle =63.96V^{\prime }lb}$
We have two unknowns here, C and V', but since the question is to find the percent submerged volume, we can relate the formula for the percentage to the obtained expressions for forces, and solve for percentage:
${\displaystyle F_b=F_w}$
${\displaystyle 57.22Vlb=63.96V^{\prime }lb}$
${\displaystyle \Rightarrow \frac{V^{\prime }}{V}=\frac{57.22}{63.96}}$
${\displaystyle =0.895}$
Since the ratio is 0.895, the percentage of submerged volume (versus the total volume) is:
${\displaystyle \because \mathrm{△}{V}^{\prime }\left(\mathrm{\%}\right)=89.5\mathrm{\%}}$

For this question starting by calculating the force of weight. But the iceberg, we can right after blue, that will be equals two specific gravity of eyes multiplied by gamma quarter, multiplied by volume. Week. Okay, so substituting the values, we get 0.917 Multiplied by £62.4.4 feet. Q. Molecular by feet. So from here we get F W equals two 57 point double too. We lb. Okay, so now buoyancy force that acts up our and opposes the force of weight is equal to F B equals two S. G.
Specific gravity of seawater Multiplied by gamma water, multiplied by redish. Okay, so substituting the values specific gravity of seawater is 1.025. multiplied by 62.4, manipulated by readers. So from here after solving we get FB equals two 63.96. Videsh held power. Now we have to announce V and whitish since the question is to find the percentage of so much volume. So uh we can relate the formula And we can write at the equals two FW.
So substituting both the values, we get 63.96 videsh that is equals to 57 point double two with. Okay, so from here we get videsh by V. That is equals to 57 point double too. They went by 63.96. And after solving, we get 0.895. Okay, so the ratio is 0.895. So the percentage of so much volume that will be equal to percentage. We dash Is equals to ${\displaystyle 89.5\mathrm{\%}}$. So this is the answer for that question. Okay, this is a lot to answer for that question.