Predict the sign of the entropy change of the system for each of the following reactions: N2(g)+3H2(g)⇒2NH3(g)

Question

Predict the sign of the entropy change of the system for each of the following reactions:  N2(g)+3H2(g)⇒2NH3(g)

Neil Dismukes · Accepted Answer

Step 1&amp;nbsp;The reaction is:&amp;nbsp;N2(g)+3H2(g)⇒2NH3(g)&amp;nbsp;According to the reaction, the product side contains fewer gaseous components than the reactant side. Therefore, the initial entropy must be higher than the final entropy. As a result, the entropy change is negative.

Toni Scott · Accepted Answer

Step 1  ΔS=Numbr of moles of gaseous product−number of moles of gaseous reactant.  Based on above expression, we can say that sign of the change in entropy of system will be positive if the number of moles of gaseous product is greater than the number of moles of gaseous reactant and vice versa.  Given reaction:  N2(g)+3H2(g)⇒2NH3(g)  ΔS for this reaction is=−2  Therefore, sign of the given reaction is negative.

nick1337 · Accepted Answer

Step 1 A decrease in entropy. Entropy is associated with the degree of disorder, or number of degrees of freedom. In the reaction N2+3H2−⇒2NH3 we start with four moles of gaseous reactants! and end with two moles of gaseous products, which is less disordered. In general, when a reaction has fewer moles of gaseous products than the moles of gaseous reactants, this will be reflected in a decrease in entropy, and vice versa. It&#039;s a good job the enthalpy change for this reaction is exothermic, or it would be impossible to make ammonia from nitrogen and hydrogen.

Predict the sign of the entropy change of the system

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