A glass plate 2.50 mm thick, with an index of refraction of 1.40, is placed between a point source of light with wavelength 540 nm (in vacuum) and a screen. The distance from source to screen is 1.80 cm. How many wavelengths are there between the source and the screen?

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Jimmy Macias · Accepted Answer

Step 1  The number of wavelength in a distance d can be calculated using the following formula:  Number of wavelengths=distan⁡cewave≤n&amp;gt;h  =dλ  And wavelength (λ) in a medium having a index of refraction n will be:  λ0n  (λ0 is wavelength in air, n is index of refraction)  Step 2  Wavelength in the glass plate will be:  λ=5401.4  ⇒λ=385.7nm  Length between source to screen is 1.8 cm, glass plate is of 2.5 mm thickness. Distance between source and screen excluding glass plate is 1.55 cm (1.88−0.25).. So the number of wavelength will be.  Number=distance  in airwavelength in air+distance in glasswavelength in glass  =1.55×10−2540×10−9+2.5×10−3385.7×10−9  =2.87×104+0.64×104  =3.51×104  Hence, the total number of wavelengths will be 3.51×104.

trisanualb6 · Accepted Answer

Answer:N=0.194Explanation:Given:- refractive index of the glass plate, n=1.4- thickness of the glass plate, x=2.5mm- wavelength of the source light, λ=18mmWe know that the refractive index of a medium is given as:n=wavelength of light in the air or vacuumwavelength of light in the mediumn=λλ′1.4=18λ′Hence the no. of wavelengths in the glass:N=xλ′N=2.512.857N=0.194

A glass plate 2.50 mm thick, with an index of

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