A glass plate 2.50 mm thick, with an index of

Adela Brown 2021-12-15 Answered
A glass plate 2.50 mm thick, with an index of refraction of 1.40, is placed between a point source of light with wavelength 540 nm (in vacuum) and a screen. The distance from source to screen is 1.80 cm. How many wavelengths are there between the source and the screen?
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Expert Answer

Jimmy Macias
Answered 2021-12-16 Author has 30 answers
Step 1
The number of wavelength in a distance d can be calculated using the following formula:
Number of wavelengths=distancewaven>h
=dλ
And wavelength (λ) in a medium having a index of refraction n will be:
λ0n
(λ0 is wavelength in air, n is index of refraction)
Step 2
Wavelength in the glass plate will be:
λ=5401.4
λ=385.7nm
Length between source to screen is 1.8 cm, glass plate is of 2.5 mm thickness. Distance between source and screen excluding glass plate is 1.55 cm (1.880.25).. So the number of wavelength will be.
Number=distance in airwavelength in air+distance in glasswavelength in glass
=1.55×102540×109+2.5×103385.7×109
=2.87×104+0.64×104
=3.51×104
Hence, the total number of wavelengths will be 3.51×104.

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trisanualb6
Answered 2021-12-17 Author has 32 answers
Answer:
N=0.194
Explanation:
Given:
- refractive index of the glass plate, n=1.4
- thickness of the glass plate, x=2.5mm
- wavelength of the source light, λ=18mm
We know that the refractive index of a medium is given as:
n=wavelength of light in the air or vacuumwavelength of light in the medium
n=λλ
1.4=18λ
Hence the no. of wavelengths in the glass:
N=xλ
N=2.512.857
N=0.194

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