The deepest point in the ocean is 11 km below sea level, deeper than MT. Everest

Kathleen Rausch 2021-12-19 Answered
The deepest point in the ocean is 11 km below sea level, deeper than MT. Everest is tall. What is the pressure in atmospheres at this depth?
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Expert Answer

vrangett
Answered 2021-12-20 Author has 36 answers
Density of sea water p=1029kgm3
Atmospheric pressure P0=1.01×105Pa
Depth h=11km=11×103m
Pressure of water at the deepest point
P=pgh=1029×9.81×11×103=1.11×108Pa
PP0=1099
Therefore net pressure =P+P0=1099+1atm=1100atm

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zesponderyd
Answered 2021-12-21 Author has 42 answers
The equation for pressure is given by:
P=P0+pgd=1.013×105+1030(9.8)(11000)=1.1×108=1.1×1081.013×105=1096atm

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Don Sumner
Answered 2021-12-27 Author has 35 answers

Concepts and reason 
The concepts required to solve the given questions is the pressure in the atmosphere at the depth.
Initially, calculate the depth form km to m. Later, write an expression for the pressure at the depth. Finally, calculate the pressure in the atmosphere at this depth. 
Fundamentals 
The expression for the atmosphere at some depth is as follows: 
Here, is the initial atmospheric pressure, D is the density of water, g is the acceleration due to gravity, and h is the deepest point in the ocean.
The depth in km is equal to, 
h=11 km
Convert it into m as follows: 
h=11 km(103 m1 km)
=11000 m
Explanation: 
The depth of the ocean is converted from km to m on multiplying by a factor of 103
Substitute 1.00 atm for P0, 1030 kg/m3 for D, 9.8m/s2 for g, and 11000 m for h in the equation P=P0+Dgh
P=1.00 atm+(1030 kg/m3)(9.8 m/s2)(11000 m)
=1.00 atm+1096.09 atm
=1097.09 atm
The pressure in the atmosphere at the depth is equal to 1097.09 atm. 
Explanation: 
The density of the water is equal to 1000 kg/m3. But we have to calculate the depth of the point in the ocean. The ocean contains salt water so, we have to use density of the salt water.

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