 # The ratio of oxygen to carbon by mass in carbon monoxide is 1.33\div1.00. Gregory Emery 2021-12-18 Answered
The ratio of oxygen to carbon by mass in carbon monoxide is $1.33÷1.00$. Find the formula of an oxide of carbon in which the ratio by mass of oxygen to carbon is $2.00÷1.00$ .
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Step 1
First , we need to find two numbers that are in a relation $2÷1$, of whith the first number is divisible with the molecular mass of the oxygen (16), while the second is divisible with the molecular mass of the carbon (12),
$2÷1=24÷12=48÷24$
Step 2
Next, to get the number of atoms of each element in a molecule ${C}_{x}{O}_{y}$, we divide the numbers we previously obtained, first one with the molecular mass of the oxygen, and the second with the molecular mass of the carbon.
$x=\frac{24}{12}=2$
$y=\frac{48}{16}=3$
Therefore, ${C}_{x}{O}_{y}={C}_{2}{O}_{3}$

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Step 1
To calculate the molecular formula, convert the mass ratio into molar ratio as follows:
mass ratio of $O÷C=2÷1$
molar mass of carbon is $12\frac{g}{mol}$ and that of oxygen is $16\frac{g}{mol}$ thus, number of moles can be calculated as follows:
$n=\frac{m}{M}$
calculating ratio,
$O÷C=\frac{2g}{16\frac{g}{mol}}÷\frac{1g}{12\frac{g}{mo;}}$
$=\frac{1}{8}÷\frac{1}{12}=12÷8=3÷2$
thus, molecular formula will be ${C}_{2}{O}_{3}$

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Step 1
The ratio of oxigen to carbon by mass in carbon monoxide is $1.33÷1.00$
Now the formula of an oxide od carbon in which the ratio by mass of mass of oxigen to carbon is $2÷1$
Here, $2÷1$
We should find the ratio of two number in which first number should be divide by 16 (as oxygen molecular mass) and should by 12 (as carbon)
Step 2
The ratio is $48÷24$
Let teh formula be ${C}_{x}{O}_{y}$
$x=\frac{24}{12}$
$y=\frac{48}{16}$

$\therefore \text{the formula will be}={C}_{2}{O}_{3}$

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