oliviayychengwh
2021-12-20
Answered

Review. An electron of mass $9.11\times 10-31$ kg has an initial speed of 3.00 $3\times 105\frac{m}{s}$ . It travels in a straight line, and its speed increases to $7.00\times 105\frac{m}{s}$ in a distance of 5.00 cm. Assuming its acceleration is constant, (a) determine the magnitude of the force exerted on the electron and (b) compare this force with the weight of the electron, which we ignored.

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Anzante2m

Answered 2021-12-21
Author has **34** answers

Ste 1

Given data:

Melinda McCombs

Answered 2021-12-22
Author has **38** answers

Step 2

(a)

First: we determine the acceleratoin by using the following equation:

${v}_{\left\{f\right\}}^{2}={v}_{\left\{i\right\}}^{2}+2a\mathrm{\u25b3}x$

Solving for (a)$a=\frac{{x}_{\left\{f\right\}}^{2}-{v}_{\left\{i\right\}}^{2}}{2\mathrm{\u25b3}x}=\frac{(7\times {10}^{5})-{(3\times {10}^{5})}^{2}}{2\times 0.05}=4\times {10}^{12}\frac{m}{{s}^{2}}$

Then: we use Newtons

(a)

First: we determine the acceleratoin by using the following equation:

Solving for (a)

Then: we use Newtons

Don Sumner

Answered 2021-12-27
Author has **35** answers

Step 3

(b)

The weight of the electron is determined by:

Therefore, this force is larger that the weight of the electron by

So,

(a)

(b)This force is larger that the weight of the electron by

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