Formic acid, HCOOH, is a weak electrolyte. What solutes are present in an aqueou

zgribestika 2021-12-20 Answered
Formic acid, HCOOH, is a weak electrolyte. What solutes are present in an aqueous solution of this compound? Write the chemical equation for the ionization of HCOOH.
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Expert Answer

rodclassique4r
Answered 2021-12-21 Author has 37 answers

Step 1
HCOOH is a weak electrolyte which means it will ionize/dissociate (not fully) in water in the following way:
HCOOH(aq)sH+(aq)+HCOO(aq)
That means we'd, in a given solution, have all three: HCOOH, H+ and HCOO

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Carl Swisher
Answered 2021-12-22 Author has 28 answers
Step 1
Formic acid is a weak electrolyte. It dissociates into HCOO and H+ ions in aqueous solution.
Step 2
Chemical equation for the ionization of HCOOH is given by,
HCOOH(aq)HCOO(aq)+H+(aq)

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Don Sumner
Answered 2021-12-27 Author has 35 answers

Step 1
Different compounds show different properties in water. Electrolytes are the compounds that dissociate in aqueous solvent to give its constituent ions.
Step 2
Strong electrolytes are those that completely dissociate in its constituent ions in aqueous solution. Whereas, weak electrolytes are those that partially dissociate in its constituent ions in aqueous solution.
HCOOH constituents the cation H+ and the anion HCOO.
Since HCOOH is a weak electrolyte, it will partially dissociate and will be in equilibrium with the constituent ions.
Write the equilibrium equation of the partial dissociation of HCOOH.
HCOOH(aq)H+(aq)+HCOO(aq)
Therefore, the solutes in the aqueous solution will be HCOOH, H+, and HCOO and the chemical equation for the ionization of HCOOH will be the same as its equilibrium equation.

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