We have the given equation is \(y=8000(1.9)^x\)

After seeing the equation it is clear that it is neither quadratic growth nor quadratic decay and it is also same for linear.

We also know that the exponential growth and decay is given by the formula

\(y=ab^x\) where ane0, the base bne1 and x is any real number.

Now, if \(b>1\)then the function represents exponential growth and if 0 Comparing the given function we get

\(a=8000\) and \(b=1.09>1\)

Therefore, we can say that the given equation is an exponential growth.