# Multiply the polynomials using the special product formulas. Express your

Multiply the polynomials using the special product formulas. Express your answer as a single polynomial in standard form.
(3x+4)(3x-4)
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Bernard Lacey
Step 1
To multiply the polynomials: (3x+4)(3x-4)
Solution:
We know that when two polynomials is multiply with each other where one polynomial is sum of two terms and other polynomial is difference of same two terms then it is equal to difference of square of two terms.
Identity is:
$\left(a+b\right)\left(a-b\right)={a}^{2}-{b}^{2}$
Therefore, multiplying the given polynomials.
$\left(3x+4\right)\left(3x-4\right)={\left(3x\right)}^{2}-{\left(4\right)}^{2}$
$=9{x}^{2}-16$
Therefore, $\left(3x+4\right)\left(3x-4\right)=9{x}^{2}-16$.
Step 2
Hence, product of (3x+4)(3x-4) is $9{x}^{2}-16$

Cleveland Walters
The given expression is of the form (x+a)(x-a). So, multiply the binomials by taking the difference of squares of the terms 3x and 4.
$\left(3x+4\right)\left(3x-4\right)={\left(3x\right)}^{2}-{4}^{2}$
Rewrite the expression using the laws of exponents and simplify.
${\left(3x\right)}^{2}-{4}^{2}={3}^{2}{x}^{2}-{4}^{2}$
$=9{x}^{2}-16$
Therefore, the result is $9{x}^{2}-16$.