Multiply the polynomials using the FOIL method. Express your answer as a single polynomial in standard form.

(2x+3y)(x-y)

(2x+3y)(x-y)

Kaspaueru2
2021-12-16
Answered

Multiply the polynomials using the FOIL method. Express your answer as a single polynomial in standard form.

(2x+3y)(x-y)

(2x+3y)(x-y)

You can still ask an expert for help

accimaroyalde

Answered 2021-12-17
Author has **29** answers

Step 1

FOIL method:

(a+b)(c+d)=ac+ad+bc+bd

Step 2

(2x+3y)(x-y)

multiplication using FOIL method:

= (2x)(x) + (2x)(-y) + (3y)(x) + (3y)(-y)

$=2{x}^{2}-2xy+3xy-3{y}^{2}$

$=2{x}^{2}+xy-3{y}^{2}$

$=2{x}^{2}+{x}^{1}y-3{y}^{2}\cdot {x}^{0}\text{}\text{}\text{}({x}^{0}=1)$

polynomial in standard form:

$(2x+3y)(x-y)=2{x}^{2}+xy-3{y}^{2}$

FOIL method:

(a+b)(c+d)=ac+ad+bc+bd

Step 2

(2x+3y)(x-y)

multiplication using FOIL method:

= (2x)(x) + (2x)(-y) + (3y)(x) + (3y)(-y)

polynomial in standard form:

lalilulelo2k3eq

Answered 2021-12-18
Author has **38** answers

Multiply the terms of the polynomials in the order First, Outer, Inner and Last.

$(2x+3y)(x-y)=2x\cdot x+2x(-y)+3y\cdot x+3y(-y)$

Use the laws of exponents to multiply the monomials.

$2x\cdot x+2x(-y)+3y\cdot x+3y(-y)=2{x}^{1+1}-2xy+3xy-3{y}^{1+1}$

$=2{x}^{2}-2xy+3xy-3{y}^{2}$

Now, combine the like terms using the distributive property.

$2{x}^{2}-2xy+3xy-3{y}^{2}=2{x}^{2}+(-2+3)xy-3{y}^{2}$

$=2{x}^{2}+xy-3{y}^{2}$

Therefore, the product is$2{x}^{2}+xy-3{y}^{2}$ .

Use the laws of exponents to multiply the monomials.

Now, combine the like terms using the distributive property.

Therefore, the product is

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