# Find all real solutions of the equation. x^{2}+24x+144=0

Find all real solutions of the equation.
${x}^{2}+24x+144=0$
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Terry Ray
Step 1
We have to find the all real solutions of the equation:
${x}^{2}+24x+144=0$
Solving the equation by factorization, we get
${x}^{2}+24x+144=0$
${x}^{2}+12x+12x+144=0$
x(x+12)+12(x+12)=0
(x+12)(x+12)=0
Step 2
Either,
x+12=0
x=-12
or,
x+12=0
x=-12
Hence, solutions of the equation are x=-12, -12.
###### Not exactly what you’re looking for?
Annie Gonzalez
Consider the following expression
${x}^{2}+24x+144=0$
Split out the term 24x into two terms such that product of these terms is equal to product of 1 and 144. Then take common terms out again.
That is,
${x}^{2}+24x+144=0$
${x}^{2}+12x+12x+144=0$
x(x+12)+12(x+12)=0
${\left(x+12\right)}^{2}=0$
(x+12)=0
x=-12
Hence the solution of the equation is -12