William Curry
2021-12-14
Answered

Factor each polynomial completely. If the polynomial cannot be factored, say it is prime.

$3{y}^{3}-18{y}^{2}-48y$

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Samantha Brown

Answered 2021-12-15
Author has **35** answers

Step 1

The given polynomial is,

$3{y}^{3}-18{y}^{2}-48y$

Taking 3y common from all the terms of the polynomial, we get

$3{y}^{3}-18{y}^{2}-48y=3y({y}^{2}-6y-16)$

Step 2

On factorizing the terms, we get

$3y({y}^{2}-6y-16)=3y({y}^{2}-8y+2y-16)$

=3y[y(y-8)+2(y-8)]

=3y(y+2)(y-8)

Therefore, the factorized form of the given polynomial is 3y(y+2)(y-8)

The given polynomial is,

Taking 3y common from all the terms of the polynomial, we get

Step 2

On factorizing the terms, we get

=3y[y(y-8)+2(y-8)]

=3y(y+2)(y-8)

Therefore, the factorized form of the given polynomial is 3y(y+2)(y-8)

hysgubwyri3

Answered 2021-12-16
Author has **43** answers

=3y(y-8)(y+2)

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