# Factor each polynomial completely. If the polynomial cannot be factored,

Factor each polynomial completely. If the polynomial cannot be factored, say it is prime.
$8{x}^{2}+88x+80$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Bukvald5z
Step 1
We have to factorize the polynomial:
$8{x}^{2}+88x+80$
Factorizing the polynomial by middle term splitting method
Here,
$80×8$
For middle term,
80+8=88
Step 2
Therefore,
$8{x}^{2}+88x+80=8{x}^{2}+80x+8x+80$
=8x(x+10)+8(x+10)
=(x+10)(8x+8)
$=\left(x+10\right)×8\left(x+1\right)$
=8(x+1)(x+10)
Hence, factorized form of the expression is 8(x+1)(x+10).
###### Not exactly what you’re looking for?
Jenny Bolton
There are many ways of factorize a polynomial. Key point is to find out the common factor from whole polynomial. Sometimes it is easy to form groups of terms in such a way that there is always one factor common in several groups. Then with the help of distributive property common factor can be factored out of each group. This technique of factorization is called factor by grouping. Sometimes there is no common factor coefficient in middle term. In such case, it is known as prime polynomial.
Objective is factor the polynomial $8{x}^{2}+88x+80$. It cannot be factored, then it is prime polynomial.
It is obviously seen first common factor is 8 in the polynomial. Take it as common factor then solve it further as given below:
$8{x}^{2}+88x+80=8\left({x}^{2}+11x+10\right)$
$=8\left({x}^{2}+10x+x+10\right)$
=8(x(x+10)+1(x+10))
=8(x+10)(x+1)
Hence, the factor of $8{x}^{2}+88x+80$ polynomial is 8(x+10)(x+1). Since it has three factors, since. The is not a prime polynomial.