Express as a polynomial. (3u-1)(u+2)+7u(u+1)

lugreget9 2021-12-16 Answered
Express as a polynomial. (3u-1)(u+2)+7u(u+1)
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Expert Answer

Nadine Salcido
Answered 2021-12-17 Author has 34 answers
Step 1
Given expression:
(3u-1)(u+2)+7u(u+1)
Step 2
Now,
A polynomial function is expressed as: anxn+an1xn1++a1x+a0
where a0,a1,..an be a real numbers and an0 and n be a non negative integer.
Expand:
(3u-1)(u+2)+7u(u+1)=3u(u+2)-1(u+2)+7u(u)+7u
=3u(u)+6uu2+7u2+7u
=3u2+6uu2+7u2+7u
=(3u2+7u2)+(6uu+7u)2
=10u2+12u2
Therefore,
Required polynomial is 10u2+12u2

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Dawn Neal
Answered 2021-12-18 Author has 35 answers
Consider the expression
(3u-1)(u+2)+7u(u+1)
This can be written as
(3u+(-1))(u+2)+(7u)(u+1)
=(3u)(u)+(3u)(2)+(-1)(4)+(-1)(2)+(7u)(u)+(7u)(1)
[Using distributive property]
=3u2+6uu2+7u2+7u [Multiplying]
=(3+7)u2+(61+7)u2 [Adding the terms of like power of x]
=10u2+12u2 [Simplifying]
Hence, the required polynomial is
10u2+12u2

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