# Which of the following is the correct factorization of 6x^{2}+x-12?

Cynthia Bell 2021-12-14 Answered
Which of the following is the correct factorization of $6{x}^{2}+x-12$?
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Thomas White
Step 1
Solution:
Given factorization of $6{x}^{2}+x-12$
Step 2
Now,
$=6{x}^{2}+x-12$
$=6{x}^{2}+9x-8x-12$
=3x(2x+3)-4(2x+3)
=(3x-4)(2x+3)
Hence
$6{x}^{2}+x-12=\left(3x-4\right)\left(2x+3\right)$ (Answer)

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accimaroyalde
Step 1
Consider the given expression.
$f\left(x\right)=6{x}^{2}+x-12$
Multiplication of 6 and 12 is 72.
$72=9×8$
Split the middle term x as 9x -8x.
We get
$f\left(x\right)=6{x}^{2}+9x-8x-12$
=3x(2x+3)-4(2x+3)
=(3x-4)(2x+3)
Step 2
Hence, the factor of the function $f\left(x\right)=6{x}^{2}+x-12$ are (3x-4) and (2x+3)

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