# Find the zeroes of the polynomial by factorization method 3x^{2}+4x-4

Find the zeroes of the polynomial by factorization method
$3{x}^{2}+4x-4$
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Andrew Reyes
Step 1 Given
$3{x}^{2}+4x-4$
Step 2 By factorization
$3{x}^{2}+6x-2x-4$
3x(x+2)-2(x+2)
(x+2)(3x-2)=0
x+2=0; 3x-2=0
x=-2; 3x=2
$x=\frac{2}{3}$
$\therefore$ Zeroes are $\frac{2}{3}$ and -2

servidopolisxv
Step 1
The given equation is
$3{x}^{2}+4x-4=0$
Step 2
To find the zero, firstly factor will be done
$3{x}^{2}+6x-2x-4=0$
3x*(x+2)-2*(x+2)=0
(3x-2)*(x+2)=0
So
3x-2=0, x+2=0
x=2/3, x=-2