# Solve absolute value inequality. 3\le |2x-1|

Solve absolute value inequality.
$3\le |2x-1|$
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vrangett
Step 1
Given inequality
$3\le |2x-1|$
Step 2
For,
$3\le 2x-1$
$4\le 2x$
$2\le x$
Step 3
For,
$3\le -\left(2x-1\right)$
$3\le -2x+1$
$2\le -2x$
$x\le -1$
Step 4
Thus, given inequality satisfies if

Jonathan Burroughs
Step 1
The given inequality is $3\le |2x-1|$
Step 2
Obtain the solution of the inequality as follows:
$3\le |2x-1|$

Thus, the solution of the inequality is $\left(-\mathrm{\infty },-1\right]\cup \left[2,\mathrm{\infty }\right)$