A sinusoidal electromagnetic wave is propagating in vacuum in the +z−direction. If at a particular instant and at a certain point in space the electric field is in the +x−direction and has magnitude 4.00Vm, what are the magnitude and direction of the magnetic field of the wave at this same point in space and instant in time?

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enlacamig · Accepted Answer

Equation (32.28) provides the Poynting vector of the energy rate in the electromagnetic wave in a vacuum in the following form:1)&amp;nbsp;S→=1μ0E→×B→&amp;nbsp;The vector product between the magnetic field and the electric field is shown in equation (1). Therefore, we use the right-hand rule when the wave comes from the opposite way to calculate the direction of the wave. The magnetic field and electric field are orthogonal to one another and the direction of transmission, respectively.Your index finger serves as a representation of the electric field&#039;s direction&amp;nbsp;+x&amp;nbsp;- direction and your thump is the direction of the propagation&amp;nbsp;+z&amp;nbsp;- direction, so your middle finger that represents the direction of magnetic field is in the direction of&amp;nbsp;+y&amp;nbsp;- axis.&amp;nbsp;+y−direction&amp;nbsp;Equation (32.4) gives the link between the maximum magnetic field and the maximum electric field in the following manner:Bmax=Emaxc&amp;nbsp;Where c denotes the light&#039;s speed. Put the values for in now.&amp;nbsp;Emax&amp;nbsp;and c to get&amp;nbsp;Bmax&amp;nbsp;Bmax=Emaxc=4.0Vm3×108ms=1.33×10−8T

stomachdm · Accepted Answer

Magnitude of magnetic field  B=Ec  =4.00Vm3×108ms  B=1.33×10−8 in the +y direction.

A sinusoidal electromagnetic wave is propagating in vacuum in the +

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