 # Calculate the frequency of each of the following wavelengths of electr Talamancoeb 2021-12-19 Answered
Calculate the frequency of each of the following wavelengths of electromagnetic radiation.
A) 632.8 nm (wavelength of red light from a helium-neon laser) Express your answer using three significant figures.
B) 503 nm (wavelength of maximum solar radiation) Express your answer using three significant figures.
C) 0.0520 nm (a wavelength used in medical X rays) Express your answer using three significant figures.
You can still ask an expert for help

• Live experts 24/7
• Questions are typically answered in as fast as 30 minutes
• Personalized clear answers

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it Cassandra Ramirez
Step 1
Given: We have to calculate the frequency of each of the following wave length of electromagnetic radiation.
A) Wave length $\left(\lambda \right)=632.8nm=632.8×{10}^{-9}m$.
Velocity $\left(c\right)=3×{10}^{8}\frac{m}{s}$
Frequency $\left(\nu \right)=?$
Now, $C=\lambda \nu$
$⇒\nu =\frac{c}{\lambda }=\frac{3×{10}^{8}}{632.8×{10}^{-9}}=4.74×{10}^{14}Hz$.
Hence, the frequency is $4.74×{10}^{14}Hz$
B) wave length $\left(\lambda \right)=503nm=503×{10}^{-9}m$
velocity $\left(c\right)=3×{10}^{8}\frac{m}{s}$
Frequency $\left(\nu \right)=?$
Now, $\nu =\frac{C}{\lambda }=\frac{3×{10}^{8}}{503×{10}^{-9}}=5.96×{10}^{14}Hz$
Hence, the frequency is $5.96×{10}^{14}Hz$
c) wave length $\left(\lambda \right)=0.052nm=0.052×{10}^{-9}m$
velocity $\left(c\right)=3×{10}^{8}\frac{m}{s}$
Frequency $\left(\nu \right)=?$
Now, $\nu =\frac{c}{\lambda }=\frac{3×{10}^{8}}{0.052×{10}^{-9}}=5.77×{10}^{18}Hz$
Hence, the frequency is $5.77×{10}^{18}Hz$

We have step-by-step solutions for your answer! Jenny Sheppard
b) We know energy of photon is given by:
$E=h\nu =\frac{hc}{\lambda }$
where, $h=\text{planles constant}$
$c=\text{speed of light}$
$\lambda =\text{wave length}$
$\nu =\text{frequency}$
$h=6.626×{10}^{-34}Js$
$c=3×{10}^{8}ms$ [on $2.998×{10}^{8}\frac{m}{s}$]
$\lambda =503nm=5.03×{10}^{-7}m$
Putting the values
$E=\frac{6.626×{10}^{-34}×3×{10}^{8}}{5.03×{10}^{-7}}J$
$E=\frac{19.878×{10}^{-19}}{5.03}$
$E=3.95×{10}^{-19}J$

We have step-by-step solutions for your answer!