The rate of disappearance of HBr in the gas phase

kihanja20 2021-12-15 Answered
The rate of disappearance of HBr in the gas phase reaction 2HBr(g)H2(g)+Br2(g) is 0.360Ms1 at 150C. The rate of reaction is ? Ms-1.
A. 1.39
B. 0.0860
C. 0.180
D. 0.130
E. 0.720
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Expert Answer

hysgubwyri3
Answered 2021-12-16 Author has 43 answers
Step 1
Since the relationship between the rate of disappearance of reactant and rate of reaction is given by rate of disappearance of reactant / reaction coefficient of reactant = rate of reaction
Step 2
Given : rate of disappearance of reactant HBr=0.360Ms
And reaction coefficient of reactant HBr=2
Rate of reaction=0.3602=0.180Ms
Hence the answer is option C

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Travis Hicks
Answered 2021-12-17 Author has 29 answers
Answer : The rate of appearance of Br2 is, 0.180 M/s
Explanation:
The general rate of reaction is,
aA+bBcC+dD
Rate of reaction: It is defined as the change in the concentration of any one of the reactants or products per unit time.
The expression for rate of reaction will be:
Rate of disappearance of A=1ad[A]dt
Rate of disappearance of B=1bd[B]dt
Rate of formation of C=+1cd[C]dt
Rate of formation of D=+1dd[D]dt
Rate=1ad[A]dt=1bd[B]dt=+1cd[C]dt=+1dd[D]dt
From this we conclude that,
In the rate of reaction, A and B are the reactants and C and D are the products.
a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.
The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.
The given rate of reaction is,
2HBr(g)H2(g)+Br2(g)
The expression for rate of reaction:
Rate of disappearance of HBr=12d[HBr]dt
Rate of appearance of H2=+d[H2]dt
Rate of apperance of Br2=+d[Br2]dt
As we are given:
Rate of disappearance of HBr=0.360Ms
+d[Br2]dt=12d[HBr]dt
d[Br2]dt=12×0.360Ms
d[Br2]dt=0.180Ms
Thus, the rate of appearance of

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