# In 2017, the population of a district was 20,800. With a continuous annual growth rate of approximately 6%, what will the population be in 2032 according to the exponential growth function? Round the answer to the nearest whole number.

In 2017, the population of a district was 20,800. With a continuous annual growth rate of approximately 6%, what will the population be in 2032 according to the exponential growth function?
Round the answer to the nearest whole number.
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In 2017, the population of a district was 20,800.
A continuous annual growth rate is of approximately 6%.
To find the population in 2032 according to the exponential growth function.
The formula for the exponential growth function is given by,
$A=P\left(1+r{\right)}^{t}$,
where A is the population after growth,
P is the initial population,
r is the yearly growth rate, and
t is time in years.
Here, P=20,800, r=6%=0.06, and t=15.
Step 3
Let, $A=P\left(1+r{\right)}^{t}$.
$=>A=20,800\left(1+0.06{\right)}^{1}5$
=20,800(2.3965)
=49,847.
$\approx 249,847$
Hence, the population in 2032 according to the exponential growth function will be 49,847.