a) one s orbital,

b) three p orbitals,

c) five d orbitals,

d) seven f orbitals.

zakinutuzi
2021-12-19
Answered

Calculate the total number of electrons that can occupy

a) one s orbital,

b) three p orbitals,

c) five d orbitals,

d) seven f orbitals.

a) one s orbital,

b) three p orbitals,

c) five d orbitals,

d) seven f orbitals.

You can still ask an expert for help

lovagwb

Answered 2021-12-20
Author has **50** answers

PART A:

The s subshell corresponds to the angular momentum quantum number$l=0$ . For a given angular momentum quantum number l, there are a maximum total of $2(2l+1)$ electrons. Therefore, an subshell has a maximum total of $2[2\left(0\right)+1]=2$ electrons.

PART B:

The p subshell corresponds to the angular momentum quantum number$l=1$ . For a given angular momentum quantum number l, there are a maximum total of $2(2l+1)$ electrons. Therefore, a p subshell has a maximum total of $2[2\left(1\right)+1]=6$ electrons.

PART C:

The d subshell corresponds to the angular momentum quantum number$l=2$ . For a given angular momentum, quantum number l, there are a maximum total of $2(2l+1)$ electrons. Therefore, a d subshell has a maximum total of $2[2\left(2\right)+1]=10$ electrons.

PART D:

The f subshell corresponds to the angular momentum quantum number$l=3$ . For a given angular momentum quantum number £, there are a maximum total of $2(2l+1)$ electrons. Therefore, an f subshell has a maximum, total of $2[2\left(3\right)+1]=14$ electrons.

The s subshell corresponds to the angular momentum quantum number

PART B:

The p subshell corresponds to the angular momentum quantum number

PART C:

The d subshell corresponds to the angular momentum quantum number

PART D:

The f subshell corresponds to the angular momentum quantum number

vicki331g8

Answered 2021-12-21
Author has **37** answers

So, electrons in the orbitals of a sub shell is given as follows, number of electrons $=2(2l+1)$

(a). for s orbital$l=0$ ,

Number of electrons$=2(2\times 0+1)$

=2 electrons

(b), Three p orbitals,$l=1$

number of electrons$=2(2\times 1+1)=6$ electrons

(c) five d orbitals,$l=2$

Number of electrons$=2(2\times 2+1)=10$ electrons

(d). seven f orbitals,$l=3$

Number of electrons$=2(2\times 3+1)=14$ electrons

(a). for s orbital

Number of electrons

=2 electrons

(b), Three p orbitals,

number of electrons

(c) five d orbitals,

Number of electrons

(d). seven f orbitals,

Number of electrons

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