Sam, whose mass is 68 kg , straps on his

Lucille Davidson 2021-12-14 Answered
Sam, whose mass is 68 kg , straps on his skis and starts down a 58 mm -high, 20∘ frictionless slope. A strong headwind exerts a horizontal force of 200 NN on him as he skis. Use work and energy to find Sam's speed at the bottom.
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Expert Answer

Neunassauk8
Answered 2021-12-15 Author has 30 answers
Given that, mass of the Sam is m=68 kg
Angle of the slope, θ=20
Height of the slope, h=58 mm
Length of the slope is given by
d=hsinθ
=58×103 msin20
=0.169 m
From work energy theorem, the net work done on the Sam will be equal to the change in kinetic energy.
WgWwd=K
The force acting on the skier is the weight of the skier downwards along the slope and the component of force along the slope. Thus the above equation is written as
[mgsinθFwcosθ]d=12mvf212mvi2
[mgsinθFwcosθ]d=12mvf20
vf2=2[mgsinθFwcosθ]dm
vf=2[mgsinθFwcosθ]dm
=2(68)(9.8)(sin20)(200)cos200.169{68}
=0.445 ms
The Sam speed at the bottom is 0.445 m/s

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