The "size" of the atom in Rutherford's model is about 1.0 \times10^

berljivx8 2021-12-14 Answered
The "size" of the atom in Rutherford's model is about 1.0×1010 m.
(a) Determine the attractive electrostatic force between an electron and a proton separated by this distance.
(b) Determine (in eV) the electrostatic potential energy of the atom. (Assume the electron and proton are again separated by the distance stated above.)
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Expert Answer

peterpan7117i
Answered 2021-12-15 Author has 39 answers
Part a)
Write the equation of electrostatic force
F=kq2r2
Missing superscript or subscript argument
F=2.304×108 N
Hence, the attractive electrostatic force is 2.304×108 N
Part b)
Write the equation of electrostatic potential energy
V=kq1q2r
V=9×109×(1.6×1019)×(1.6×1019}{(1.0×1.010 m)}
V=2.304×1018×(1eV1.6×1019J)
V=14.3eV

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