abreviatsjw
2021-12-15
Answered

Two protons, starting several meters apart, are aimed directly at each other with speeds of $2.00\cdot {10}^{5}\text{}\frac{m}{s}$ , measured relative to the earth. Find the maximum electric force that these protons will exert on each other.

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Bukvald5z

Answered 2021-12-16
Author has **33** answers

speed, $v=2\times {10}^{5}\text{}\frac{m}{s}$

speed,$v=2\times {10}^{5}\text{}\frac{m}{s}$

Let the distance is r.

Use conservation of energy

KE = Potential energy

$2x\frac{1}{x}m{v}^{2}=\frac{k{e}^{2}}{r}$

$r=\frac{k{e}^{2}}{m{v}^{2}}=\frac{9\times {10}^{9}\times 1.6\times 1.6\times {10}^{-38}}{1.67\times {10}^{-27}\times 2\times 2\times {10}^{10}}$

$r=3.5\times {10}^{-12}\text{}m$

Let the force is F.

$F=\frac{k{e}^{2}}{{r}^{2}}$

$F=\frac{9\times {10}^{9}\times 1.6\times 1.6\times {10}^{-38}}{3.5\times 3.5\times {10}^{-24}}$

$F=1.88\times {10}^{-5}\text{}N$

speed,

Let the distance is r.

Use conservation of energy

KE = Potential energy

Let the force is F.

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