# Calculate the nuclear binding energy of M_n(A=55,\ z=25) in joul

Calculate the nuclear binding energy of in joules.
The atomic mass of 5525Mn is 54.938 amu
The speed of light is
The mass of a proton is 1.0073 amu
The mass of a neutron is 1.0087 amu
The mass of an electron is

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Carl Swisher
The number of the neutrons of the substance is
$N=A-Z$
$=55-25$
$=30$
The expression for the final mass of the substance is
${m}_{f}=Z\left({m}_{p}\right)+N\left({m}_{n}\right)$

$=55.4435$
The difference in mass is
$\mathrm{△}m={m}_{f}-{m}_{i}$

$=0.5055a\mu \left(\frac{1.66×{10}^{-27}kg}{1a\mu }\right)$
$=8.39×{10}^{-28}kg$
The binding energy is
$BE=\mathrm{△}m{c}^{2}$
$=\left(8.39×{10}^{-28}kg\right){\left(3×{10}^{8}\frac{m}{s}\right)}^{2}$
$=7.55×{10}^{-11}J$