# At boiling of water, the vapor pressure becomes equivalent ot

At boiling of water, the vapor pressure becomes equivalent ot atmospheric pressure. The vapor pressure can be determined as:
$\mathrm{log}P=A-\left[\frac{B}{C+T}\right]$
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Donald Cheek
where, P is pressure
A = 8.071
B = 1730.63
C = 233.426
T = 81 The pressure can be determined as:
$\mathrm{log}P=A-\left[\frac{B}{C+T}\right]$
$\mathrm{log}P=8.071-\left[\frac{1730.63}{233.426+81}\right]$
$\mathrm{log}P=8.071-5.504=2.568$

Thus, atmospheric pressure of water is 368.89 mmHg