# Gas Y effuses half as fast as O2. What is

Gas Y effuses half as fast as O2. What is the molar mass of gas Y?
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Lindsey Gamble

Given, gas Y effuses half as fast as O2.
The molar mass of gas Y is calculated by using Graham's law.
${\left(\frac{{R}_{1}}{{R}_{2}}\right)}^{2}=\frac{{M}_{2}}{{M}_{1}}$
where,
${R}_{1}$ and ${R}_{2}$ =rates of diffusion
${M}_{1}=$ molar mass of ${O}_{2}$
${M}_{2}=$ = molar mass of gas Y
The molar mass of gas Y is
${\left(\frac{2}{1}\right)}^{2}=\frac{{M}_{2}}{32}$
$\frac{4}{1}=\frac{{M}_{2}}{32}$
${M}_{2}=32×4$

Molar mass of gas