A ball is thrown vertically upward with a speed of

A ball is thrown vertically upward with a speed of 25.0 m/s. How long does the ball take to hit the ground after it reaches its highest point?
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intacte87
Now if we measure the time to reach from heighest point point to the ground after reaching the heighest point, the initial vertical speed of the ball
The ball is moving under gravitational force, so the acceleration of the ball
From part (a), the maximum height up to which the ball can reach
Now the time taken by the ball to reach the ground can be calculated from the eqaution
$S={v}_{i}t+\frac{1}{2}a{t}^{2}$
$=0×t+\frac{1}{2}a{t}^{2}$
$=\frac{1}{2}a{t}^{2}$
Therefore from the above equation, we get
$t=\sqrt{\frac{2S}{a}}$

Which is same as calculated in part(b) for to reach the ball to its maximum hight from ground.
Result: c)