An electron is accelerated from rest by a potential difference

Stacie Worsley 2021-12-16 Answered
An electron is accelerated from rest by a potential difference of 350 V. It then enters a uniform magnetic field of magnitude 200 mT with its velocity perpendicular to the field. Calculate (a) the speed of the electron and (b) the radius of its path in the magnetic field.
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Expert Answer

Mary Herrera
Answered 2021-12-17 Author has 37 answers
a) Assume we have an electron accelerated using potential difference of V=350 V, which gives the ion a speed of v, to find this speed we set the potential energy equals to the kinetic energy of the ion:
eV=12mv2
v=2eVm
substitute with the givens to get:
v=2(1.6×1019 C)(350 V)9.11×1031 kg
=1.11×107 ms
b) Then the electron enters a region of uniform magnetic field, it moves in circular path with radius of:
r=mveB
substitute with givens to get:
r=(9.11×1031 kg)(1.11×107 ms)(1.6×1019 C)(200×103 T)
=3.16×104 m
r=3.16×104 m
Result: a) v=1.11×107 ms
b) r=3.16×104 m

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