${x}^{2}-4x-12$
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MoxboasteBots5h
The given quadratic polynomial is ${x}^{2}-4x-12$.
It is factored as follows.
${x}^{2}-4x-12={x}^{2}-6x+2x-12$
=x(x-6)+2(x-6)
=(x+2)(x-6)
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Joseph Fair
The given equation is:
${x}^{2}-4x-12$
$⇒{x}^{2}-4x=12$
Thus,
${x}^{2}-4x=12$
$⇒{x}^{2}-4x-12=0$
The product of the second degree term and the constant is $-12{x}^{2}$. Factors of $-12{x}^{2}$ that sum to -4x are -6x and 2x. Thus,
Factorizing which we get,
${x}^{2}-4x-12=0$
$⇒{x}^{2}-6x+2x-12=0$
$⇒x\left(x-6\right)+2\left(x-6\right)=0$
$⇒\left(x-6\right)\left(x+2\right)=0$
The required values of x are 6 and -2.