# Factor the polynomials. 3x^{2}-21x+30

feminizmiki 2021-12-15 Answered
Factor the polynomials.
$3{x}^{2}-21x+30$
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## Expert Answer

Jim Hunt
Answered 2021-12-16 Author has 45 answers
Consider the given polynomial:
$3{x}^{2}-21x+30$
Now, splitting the middle term, we get,
$3{x}^{2}-21x+30$
$=3{x}^{2}-15x-6x+30$
=3x(x-5)-6(x-5)
=(x-5)(3x-6)
=3(x-5)(x-2)
Hence, the given polynomial is factorised as:
$3{x}^{2}-21x+30=3\left(x-5\right)\left(x-2\right)$

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twineg4
Answered 2021-12-17 Author has 33 answers
Given:
$3{x}^{2}-21x+30$
$3\left({x}^{2}-7x+10\right)$
Use the sum of the products
$3\left({x}^{2}-7x+10\right)$
$3\left({x}^{2}-2x-5x+10\right)$
Find the common factor for two pairs
$3\left({x}^{2}-2x-5x+10\right)$
3(x(x-2)-5(x-2))
Multiply by factors
3(x(x-2)-5(x-2))
3(x-5)(x-2)
The solution:
3(x-5)(x-2)

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