# Factor the polynomials. x^{2}-6x+9

Factor the polynomials.
${x}^{2}-6x+9$
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scomparve5j
Consider the given polynomial:
${x}^{2}-6x+9$
Now, splitting the middle term, we get,
${x}^{2}-6x+9$
$={x}^{2}-3x-3x+9$
=x(x-3)-3(x-3)
=(x-3)(x-3)
Hence, the given polynomial is factorised as:
${x}^{2}-6x+9=\left(x-3\right)\left(x-3\right)$
###### Did you like this example?
Jacob Homer
${a}^{2}-2\cdot a\cdot b+{b}^{2}={\left(a-b\right)}^{2}$
${a}^{2}-2\cdot a\cdot b+{b}^{2}={\left(a-b\right)}^{2}$ Write the Prefect Square Trinomial
${x}^{2}-2\cdot x\cdot 3+{3}^{2}={\left(x-3\right)}^{2}$ Substitute a=x and b=3.
Result:
${\left(x-3\right)}^{2}$